I have R5F212L4SNFP MCU & E8 debugger (not E8a).I have made a breakout circuit for this MCU.
1. Is this the minimum circuit ok?2. I have added 4.7K/0.1uF for reset circuit, it is ok? Hardware manual says 4.7k or more. It dont specify 0.1uF cap3. Mode pull resistor is 4.7uF4. Vcc & Vss decoupled by 0.1u+10u
Below image is for E8 used with R5F212L4SNFP. Do it give full step by step debug capability using E8 or any other pin required?
The E8 isn't supported with drivers on Windows 7 64 bit or newer. You'd have to use XP 32 bit for development.
In reply to Calvin Grier:
I am using Window 7 32 bit. I have ordered some pieces of MCU, will solder & then try to use E8 debugger on it. However E8 get detected on window 7 32 bit.
Also as I have asked is selection of 4.7k/0.1uF for reset & 4.7k for mode is ok?
Is this is the minimum circuit with which device will work as I am making a minium breakout baord.